zad 24
a) [tex]\frac{3}{6} + \frac{2}{6} = \frac{5}{6}[/tex]
b) [tex]1\frac{5}{8} + 2\frac{3}{8} = 3\frac{8}{8} = 4[/tex]
c) [tex]6 - \frac{2}{7} = 5\frac{7}{7} - \frac{2}{7} = 5\frac{5}{7}[/tex]
d) [tex]\frac{1}{4} - \frac{1}{8} = \frac{2}{8} - \frac{1}{8} = \frac{1}{8}[/tex]
e) [tex]6\frac{1}{2} - 1\frac{1}{4} = 6\frac{2}{4} - 1\frac{1}{4} = 5\frac{1}{4}[/tex]
f) [tex]5 - 3\frac{3}{7} = 4\frac{7}{7} - 3\frac{3}{7} = 1\frac{4}{7}[/tex]
zad 25
a) [tex]\frac{1}{6} + \frac{2}{5} = \frac{5}{30} + \frac{12}{30} = \frac{17}{30}[/tex]
b) [tex]\frac{8}{9} - \frac{5}{6} = \frac{48}{54} - \frac{45}{54} = \frac{3}{54} = \frac{1}{18}[/tex]
c) [tex]1\frac{1}{5} + 8\frac{1}{7} = 1\frac{7}{35} + 8\frac{5}{35} = 9\frac{12}{35}[/tex]
d) [tex]4\frac{7}{10} - 2\frac{1}{3} = 4\frac{21}{30} - 2\frac{10}{30} = 2 \frac{11}{30}[/tex]
e) [tex]4\frac{1}{5} - \frac{7}{10} = 4\frac{2}{10} - \frac{7}{10} = 3\frac{12}{10} - \frac{7}{10} = 3\frac{5}{10} = 3\frac{1}{2}[/tex]
f) [tex]6\frac{1}{8} - 2\frac{3}{4} = 6\frac{1}{8} - 2\frac{6}{8} = 5\frac{9}{8} - 2\frac{6}{8} = 3\frac{3}{8}[/tex]
g) [tex]10\frac{2}{3} - 6\frac{7}{9} = 10\frac{6}{9} - 6\frac{7} {9} = 9\frac{15}{9} - 6\frac{7} {9} = 3 \frac{8}{9}[/tex]
h) [tex]9\frac{3}{8} - 2\frac{5}{6} = 9\frac{9}{24} - 2\frac{20}{24} = 8\frac{33}{24} - 2\frac{20}{24} = 6\frac{13}{24}[/tex]
