Odpowiedź :
Odpowiedź:
a)
[tex]10.6 - 4 \frac{2}{3} + 16 \frac{1}{15} = 10 \frac{6}{10} - \frac{14}{3} + \frac{241}{15} = \frac{53}{5} - \frac{14}{3} + \frac{241}{15} = \frac{159 - 70 + 241}{15} = \frac{330}{15} = 22[/tex]
b)
[tex]6 \frac{1}{2} + (3 \frac{1}{3} - \frac{1}{2} ) \div 2 \frac{5}{6} - 1 \frac{3}{4} = \frac{13}{2} + ( \frac{10}{3} - \frac{1}{2} ) \div \frac{17}{6} - \frac{7}{4} = \frac{13}{2} + \frac{20 - 3}{6} \times \frac{6}{17} - \frac{7}{4} = \frac{13}{2} + 1 - \frac{7}{4} = \frac{15}{2} - \frac{7}{4} = \frac{30 - 7}{4} = \frac{23}{4} [/tex]