Odpowiedź:
a)
[tex] {( \frac{1}{7} )}^{2} \times {14}^{2} - {10}^{5} \times {( \frac{1}{5}) }^{5} = {( \frac{1}{7} \times 14)}^{2} - {(10 \times \frac{1}{5}) }^{5} = {2}^{2} - {2}^{5} = 4 - 32 = - 28[/tex]
b)
[tex] {35}^{2} \div {( - 7)}^{2} + {( - 6)}^{3} \div {( - 2)}^{3} = {(35 \div ( - 7))}^{2} + {( - 6 \div ( - 2))}^{3} = {( - 5)}^{2} + {3}^{3} = 25 + 27 = 52[/tex]
c)
[tex] {4}^{2} \times {( \frac{1}{4}) }^{2} - {( \frac{1}{5}) }^{3} \times {5}^{3} = {(4 \times \frac{1}{4}) }^{2} - {( \frac{1}{5} \times 5)}^{3} = {1}^{2} - {1}^{3} = 1 - 1 = 0[/tex]
d)
[tex] {( \frac{3}{7} )}^{3} \div {( - \frac{6}{7} )}^{3} - {15}^{4} \div {( - 5)}^{4} = {( \frac{3}{7} \div ( - \frac{6}{7})) }^{3} - {(15 \div ( - 5))}^{4} = {( - \frac{1}{2}) }^{3} - {( - 3)}^{4} = - \frac{1}{8} - 81 = - 81 \frac{1}{8} [/tex]
