Odpowiedź:
c)
[tex] \sqrt{3} ( \sqrt{6} - \sqrt{2} ) + \frac{1}{ \sqrt{6} } ( \sqrt{3} - 2 \sqrt{2} ) = \sqrt{18} - \sqrt{6} + \frac{ \sqrt{3} }{ \sqrt{6} } - \frac{2 \sqrt{2} }{ \sqrt{6} } = 3 \sqrt{2} - \sqrt{6} + \frac{ \sqrt{18} }{6} - \frac{2 \sqrt{12} }{6} = 3 \sqrt{2} - \sqrt{6} + \frac{3 \sqrt{2} }{6} - \frac{4 \sqrt{3} }{6} = \frac{7}{2} \sqrt{2} - \sqrt{6} - \frac{2}{3} \sqrt{3} [/tex]
d)
[tex] \sqrt{10} ( \sqrt{5} + 2 \sqrt{2} ) - \frac{ \sqrt{45} - \sqrt{20} }{ \sqrt{5} } = \sqrt{50} + 2 \sqrt{20} - \sqrt{9} + \sqrt{4} = 5 \sqrt{2} + 4 \sqrt{5} - 3 + 2 = 5 \sqrt{2} + 4 \sqrt{5} - 1[/tex]
