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Ilość wyrażenia i oblicz.
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Ilość Wyrażenia I Oblicz class=

Odpowiedź :

Unicorn05

a)

  [tex]\dfrac{2^6+2^5}{12}=\dfrac{2\cdot2^5+2^5}{12}=\dfrac{2^5(2+1)}{12}=\dfrac{2^5\cdot3}{12} =\dfrac{2^5}{4}=\dfrac{2^5}{2^2}=2^3=8[/tex]

b)

 [tex]\dfrac{8^2\cdot3^6}{6^5}=\dfrac{(2^3)^2\cdot3^6}{6^5}= \dfrac{2^6\cdot3^6}{6^5} =\dfrac{(2\cdot3)^6}{6^5}=\dfrac{6^6}{6^5}=6^1=6[/tex]

Basetla

[tex]a) \ \frac{2^{6}+2^{5}}{12} =\frac{2^{5}\cdot2+2^{5}}{12} = \frac{2^{5}(2+1)}{12} = \frac{3\cdot2^{5}}{12} = \frac{2^{5}}{4} =\frac{2^{5}}{2^{2}} = 2^{5-2} = 2^{3} = 8\\\\\\b) \ \frac{8^{2}\cdot3^{6}}{6^{5}} = \frac{(2^{3})^{2}\cdot3^{6}}{6^{5}} = \frac{2^{6}\cdot3^{6}}{6^{5}} =\frac{(2\cdot3)^{6}}{6^{5}} = \frac{6^{6}}{6^{5}} = 6^{6-5} = 6^{1} = 6[/tex]

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