Cześć ;-)
Od a) do c)
[tex](x-1)^2=x^2-2\cdot x\cdot1+1^2=\underline{x^2-2x+1}\\\\(x-3)^2=x^2-2\cdot x\cdot3+3^2=\underline{x^2-6x+9}\\\\(2x-2)^2=(2x)^2-2\cdot2x\cdot2+2^2=\underline{4x^2-8x+4}[/tex]
Od d) do f)
[tex](4x-7)^2=(4x)^2-2\cdot4x\cdot7+7^2=\underline{16x^2-56x+49}\\\\(x-3y)^2=x^2-2\cdot x\cdot3y+(3y)^2=\underline{x^2+3y^2-6xy}\\\\(3x-y)^2=(3x)^2-2\cdot3x\cdot y+y^2=\underline{9x^2+y^2-6xy}[/tex]
Pozdrawiam!
