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[tex](\frac{5}{8}\cdot\frac{15}{4}):\frac{6}{5}=\frac{75}{32}:\frac{6}{5}=\frac{\not75^{25}}{32}\cdot\frac{5}{\not6_2}=\frac{125}{64}=1\frac{61}{64}\\\\(\frac{1}{2}\cdot\frac{1}{3}):\frac{1}{6}=\frac{1}{6}:\frac{1}{6}=\frac{1}{6}\cdot6=1\\\\(\frac{\not2^1}{3}\cdot\frac{5}{\not6_3}):\frac{9}{15}=\frac{5}{9}:\frac{9}{15}=\frac{5}{\not9_3}\cdot\frac{\not15^5}{9}=\frac{25}{27}[/tex]
[tex]1\frac{2}{3}:8\frac{4}{7}=\frac{5}{3}:\frac{60}{7}=\frac{\not5^1}{3}\cdot\frac{7}{\not60_{12}}=\frac{7}{36}\\\\(2\frac{6}{7}:1\frac{3}{7})\cdot\frac{1}{2}=(\frac{20}{7}:\frac{10}{7})\cdot2=(\frac{\not20^2}{\not7^1}\cdot\frac{\not7_1}{\not10_1})\cdot\frac{1}{2}=7\cdot\frac{1}{2}=\frac{7}{2}=3\frac{1}{2}[/tex]
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Odpowiedź:
h) (5/8×15/4)÷6/5= (1/2×3)÷6/5 = 3/2 ÷6/5= 3/2 × 5/6 = 1/2 × 5/2= 5/4 = 1 1/4
i) (1/2 ×1/3)÷1/6 = 1/6÷1/6= 1/6 × 6 = 1
j) (2/3×5/6)÷9/15 = 10/18 ÷ 9/15 = 2 ÷ 1/3 = 2 × 3= 6
k) 1 2/3÷8 4/7 = 5/3 ÷ 60/7 = 5/3 × 7/60 = 1/3 × 7/12 = 7/36
l) (2 6/7÷1 3/7)×1/2 = (20/7÷10/7)×1/2 = (20/7×7/10)×1/2 = 2×1/2 = 1