Odpowiedź :
[tex]dane:\\t = 1 \ min = 60 \ s\\W = 120 \ kGm = \frac{120}{0,1} \ J = 1200 \ J\\1 \ J\approx0,1 \ kGm\\szukane:\\P = ?\\\\P = \frac{W}{t}\\\\P = \frac{1200 \ J}{60 \ s}\\\\P = 20 \ W[/tex]
[tex]dane:\\t = 1 \ min = 60 \ s\\W = 120 \ kGm = \frac{120}{0,1} \ J = 1200 \ J\\1 \ J\approx0,1 \ kGm\\szukane:\\P = ?\\\\P = \frac{W}{t}\\\\P = \frac{1200 \ J}{60 \ s}\\\\P = 20 \ W[/tex]