Odpowiedź :
gęstość -> 1,26 g przypada na 1 cm3
76 g 22,4 dm3 44,8 dm3
CS2 + 3 O2 = CO2 + 2 SO2
1,26 g x y
76 g CS2 --- 22,4 dm3 CO2
1,26 g CS2 --- x
--------------------------------
x = 0,37 dm3 CO2 (warunki normalne)
76 g CS2 --- 44,8 dm3 SO2
1,26 g CS2 --- y
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y = 0,74 dm3 SO2 (warunki normalne)
[tex]\frac{p_{1}V_{1}}{T_{1}}=\frac{p_{2}V_{2}}{T_{2}}[/tex]
[tex]p_{1}V_{1}T_{2}=T_{1}p_{2}V_{2}/:(T_{1}p_{2})[/tex]
[tex]V_{2}=\frac{p_{1}V_{1}T_{2}}{T_{1}p_{2}}[/tex]
V1 = 0,37 dm3 CO2 lub 0,74 dm3 SO2
p1 = 1013,25 hPa
T1 = 25 'C
V2 = ?
p2 = 1200 hPa
T2 = 40 'C
[tex]V_{2}=\frac{1013,25 hPa*0,37 dm^{3}*40'C}{25'C*1200 hPa}=0,50 dm^{3} CO2[/tex]
[tex]V_{2}=\frac{1013,25 hPa*0,74 dm^{3}*40'C}{25'C*1200 hPa}= 1dm^{3} SO2[/tex]
