Odpowiedź:
[tex]\sqrt{2\frac{7}{9}}\cdot3+(\frac{3}{4})^{-1}:(-\frac{2}{3})^3=\sqrt{\frac{25}{9}}\cdot3+(\frac{4}{3})^1:(-\frac{8}{27})=\frac{5}{\not3}\cdot{\not3}+\frac{\not4^1}{\not3_{1}}\cdot(-\frac{\not27^9}{\not8_{2}})=5-\frac{9}{2}=\\\\=5-4\frac{1}{2}=4\frac{2}{2}-4\frac{1}{2}=\frac{1}{2}[/tex]
