d)
[tex](3,8-5:1\frac{1}{3})+1\frac{3}{4}=(3,8-5:\frac{4}{3})+1\frac{3}{4}=\\\\=(3,8-5\cdot\frac{3}{4})+1\frac{3}{4}=(3,8-\frac{15}{4})+1\frac{3}{4}=\\\\=(3,8-3\frac{3}{4})+1\frac{3}{4}=(3,8-3\frac{75}{100})+1\frac{75}{100}=\\\\=(3,8-3,75)+1,75=0,05+1,75=1,8[/tex]
e)
[tex]3\frac{1}{2}\cdot(0,6-\frac{1}{2})=\frac{7}{2}\cdot(0,6-\frac{5}{10})=\\\\=\frac{7}{2}\cdot(0,6-0,5)=\frac{7}{2}\cdot0,1=\frac{7}{2}\cdot\frac{1}{10}=\frac{7}{20}[/tex]
f)
[tex]-3\frac{2}{3}+1\frac{1}{2}=-(3\frac{2}{3}-1\frac{1}{2})=\\\\=-(3\frac{4}{6}-1\frac{3}{6})=-2\frac{1}{6}[/tex]
g)
[tex]\frac{(-\frac{1}{3})^2-0,6:\frac{3}{5}}{5-8}=\frac{\frac{1}{9}-0,6:\frac{6}{10}}{-(8-5)}=\frac{\frac{1}{9}-0,6:0,6}{-3}=\\\\=\frac{\frac{1}{9}-1}{-3}=\frac{\frac{1}{9}-\frac{9}{9}}{-3}=\frac{-\frac{8}{9}}{-3}=-\frac{8}{9}\cdot(-\frac{1}{3})=\frac{8}{27}[/tex]
