[tex]\frac{-3(-2-10)-1}{6-8}=\\\\=\frac{6+30-1}{-2}=\\\\=\frac{35}{-2}\\\\=\boxed{-17\frac{1}{2}=-17{,}5}[/tex]
Obliczenia
[tex]\dfrac{-3\cdot(-2-10)-1}{6-8}=\dfrac{-3\cdot(-12)-1}{-2}=\dfrac{36-1}{-2}=\dfrac{35}{-2}=\huge\boxed{-17,5}\\\\\\:)[/tex]
