Obliczenia
[tex]1\frac{2}{3}+\frac{3}{4}=1\frac{8}{12}+\frac{9}{12}=1\frac{17}{12}=2\frac{5}{12}\\\\1\frac{3}{5}-\frac{3}{10}=1\frac{6}{10}-\frac{3}{10}=1\frac{3}{10}\\\\1\frac{2}{7}\cdot3\frac{1}{3}=\frac{\not9^3}{7}\cdot\frac{10}{\not3_1}=\frac{30}{7}=4\frac{2}{7}\\\\1\frac{2}{3}:\frac{5}{12}=\frac{\not5^1}{\not3_1}\cdot\frac{\not12^4}{\not5_1}=4[/tex]
