Obliczenia
[tex](\frac{1}{2}-\frac{1}{6})^2+(\frac{1}{2})^2=(\frac{3}{6}-\frac{1}{6})^2+\frac{1^2}{2^2}=\\\\=(\frac{2}{6})^2+\frac{1}{4}=(\frac{1}{3})^2+\frac{1}{4}=\frac{1^2}{3^2}+\frac{1}{4}=\\\\=\frac{1}{9}+\frac{1}{4}=\frac{4}{36}+\frac{9}{36}=\frac{13}{36}[/tex]
