[tex]-0,5x^{2}+4x= 6\\\\-0,5x^{2}+4x-6 = 0 \ \ /\cdot(-1)\\\\\underline{0,5x^{2}-4x+6 = 0}\\\\a = 0,5, \ \ b = -4, \ \ c = 6\\\\\Delta = b^{2}-4ac =(-4)^{2}-4\cdot0,5\cdot6 = 16 - 12 = 4\\\\\sqrt{\Delta} = \sqrt{4} = 2\\\\x_1 = \frac{-b-\sqrt{\Delta}}{2a} = \frac{-(-4)-2}{2\cdot0,5} = \frac{2}{1} = 2\\\\x_2 = \frac{-(-b)+\sqrt{\Delta}}{2a} = \frac{-(-4)+2}{2\cdot0,5} = \frac{6}{1} = 6\\\\x \in \{2, 6\}[/tex]
