Odpowiedź:
[tex] \frac{3 \frac{1}{4} + \frac{2}{4} }{3 \frac{1}{2} \times (1 \frac{10}{12} - 1 \frac{1}{12}) } = \frac{3 \frac{3}{4} }{ \frac{7}{2} \times \frac{9}{12} } = \frac{15}{4} \div \frac{63}{24} = \frac{15}{4} \times \frac{24}{63} = \frac{90}{63} = 1 \frac{27}{63} [/tex]
