[tex]dane:\\q_1 = 6 \ nC =6\cdot10^{-9} \ C\\q_2 = 8 \ nC = 8\cdot10^{-9} \ C\\r = 40 \ cm = 0,4 \ m =4\cdot10^{-1} \ m\\k = 9\cdot10^{9} \ \frac{Nm^{2}}{C^{2}}\\szukane:\\F = ?\\\\Rozwiazanie\\\\F = k\cdot\frac{q_1 \cdot q_2}{r^{2}}\\\\F = 9\cdot10^{9}\frac{Nm^{2}}{C^{2}}\cdot\frac{6\cdot10^{-6} \ C\cdot 8\cdot10^{-9} \ C}{(4\cdot10^{-1} \ m)^{2}}[/tex]
[tex]F = 27\cdot10^{-7} \ N[/tex]
