[tex]30\cdot2^{20}+32^5+2^{21}=15\cdot2\cdot2^{20}+(2^5)^5+2^{21}=\\\\15\cdot2^{21}+2^{25}+2^{21}=15\cdot2^{21}+1\cdot2^{21}+2^{25}=\\\\2^{21}(15+1)+2^{25}=2^{21}\cdot16+2^{25}=2^{21}\cdot2^4+2^{25}=\\\\2^{25}+2^{25}=2\cdot2^{25}=2^{26}[/tex]
