Rozwiązanie równania
[tex]\sqrt5(x-\sqrt5)=10-x\\\\\sqrt5x-(\sqrt5)^2=10-x\\\\\sqrt5x-5=10-x\\\\\sqrt5x+x=10+5\\\\x(\sqrt5+1)=15 \ \ /:\sqrt5+1\\\\x=\frac{15}{\sqrt5+1}=\frac{15}{\sqrt5+1}\cdot\frac{\sqrt5-1}{\sqrt5-1}=\frac{15\sqrt5-15}{5-1}\\\\\huge\boxed{x=\frac{15\sqrt5-15}{4}}[/tex]
