[tex]dane:\\m = 0,4 \ kg\\k = 10\frac{N}{m}\\szukane:\\T = ?\\\\Rozwiazanie\\\\T = 2\pi\sqrt{\frac{m}{k}}\\\\T = 2\cdot3,14\cdot\sqrt{\frac{0,4 \ kg}{10\frac{N}{m}}} = 6,28\cdot\sqrt{\frac{0,4 \ kg}{10 \frac{\frac{kg\cdot m}{s^{2}}}{m}}}=6,28\cdot\sqrt{0,04 \ s^{2}} =6,28\cdot0,2 \ s\\\\\underline{T = 1,256 \ s}[/tex]
Odp. Okres T = 1,256 s.
