[tex]dane:\\Q = 13,36 \ MJ = 13 \ 360 \ 000 \ J\\c_{t} = 334 \ 000 \ \frac{J}{kg} \ - \ cieplo \ topnienia \ lodu\\szukane:\\m = ?\\\\Q = m\cdot c_{t} \ \ /:c_{t}\\\\m = \frac{Q}{c_{t}}\\\\m = \frac{13 \ 360 \ 000 \ J}{334 \ 000 \ \frac{J}{kg}}\\\\\underline{m = 40 \ kg}[/tex]