Odpowiedź:
[tex]\frac{1}{4}\sqrt{128}-\sqrt{32}+\sqrt{50}=\frac{1}{4}\sqrt{64\cdot2}-\sqrt{16\cdot2}+\sqrt{25\cdot2}=\frac{1}{\not4_{1}}\cdot\not8^2\sqrt{2}-4\sqrt{2}+5\sqrt{2}=\\\\=2\sqrt{2}-4\sqrt{2}+5\sqrt{2}=-2\sqrt{2}+5\sqrt{2}=3\sqrt{2}\\\\Odp.C[/tex]
