Odpowiedź :
[tex]zad.a\\\\\dfrac{2}{5} \div 3=\dfrac{2}{5} \cdot \dfrac{1}{3} =\dfrac{2}{15} \\\\zad.b\\\\2\dfrac{2}{5} \div 4=\dfrac{12}{5} \div 4=\dfrac{12}{5} \cdot \dfrac{1}{4}=\dfrac{3}{5}\\\\zad.d\\\\\dfrac{8}{7}\div \dfrac{20}{21}=\dfrac{8}{7}\cdot \dfrac{21}{20}==\dfrac{6}{5}=1\dfrac{1}{6} \\\\zad.c\\\\\dfrac{3}{5} \div \dfrac{4}{7} =\dfrac{3}{5} \cdot \dfrac{7}{4}=\dfrac{21}{20}=1\dfrac{1}{20}\\\\zad.e\\\\[/tex]
[tex]1\dfrac{2}{7} \div \dfrac{4}{5} =\dfrac{9}{7} \div \dfrac{4}{5}=\dfrac{9}{7} \cdot \dfrac{5}{4} =\dfrac{45}{28} =1\dfrac{17}{28} \\\\zad.f\\\\2\dfrac{7}{10} \div1 \dfrac{2}{7} =\dfrac{27}{10} \div \dfrac{9}{7} =\dfrac{27}{10}\cdot \dfrac{7}{9} =\dfrac{21}{10} =2\dfrac{1}{10} \\\\zad.g\\\\3\dfrac{3}{4} \div 1\dfrac{7}{8} =\dfrac{15}{4} \div \dfrac{15}{8} =\dfrac{15}{4}\cdot \dfrac{8}{15}=2\\[/tex]