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Zad.5.Zapisz w postaci jednej potęgi:
a)0,2^4•0,2^5=
b)2,3^9:2,3^3=
c)(-5^6)^5=
d)(12/25)^7•(5/18)^7=
e)7^9•3^9=
f)15^3:5^3=
Na teraz plis!!!



Odpowiedź :

Mokuss

Odpowiedź:

a)

[tex] {0.2}^{4} \times {0.2}^{5} = {0.2}^{4 + 5} = {0.2}^{9} [/tex]

b)

[tex] {2.3}^{9} \div {2.3}^{3} = {2.3}^{9 - 3} = {2.3}^{6} [/tex]

c)

[tex] { ({ - 5}^{6} })^{5} = {( - 5)}^{5 \times 6} = {( - 5)}^{30} [/tex]

d)

[tex] {( \frac{12}{25}) }^{7} \times ( { \frac{5}{18} })^{7} = ( { \frac{12}{25} \times \frac{5}{18} })^{7} = ( { \frac{2}{5} \times \frac{1}{3} })^{7} = ({ \frac{2}{15} })^{7} [/tex]

e)

[tex] {7}^{9} \times {3}^{9} = ( {7 \times 3})^{9} = {21}^{9} [/tex]

f)

[tex] {15}^{3} \div {5}^{3} = ({15 \div 5})^{3} = {3}^{3} [/tex]