Obliczenia
[tex]\sqrt{1\frac{9}{16}}=\sqrt{\frac{25}{16}}=\frac{\sqrt{25}}{\sqrt{16}}=\frac{\sqrt{5^2}}{\sqrt{4^2}}=\frac{5}{4}=\boxed{1,25}\\\\\\\sqrt{144+25}=\sqrt{169}=\sqrt{13^2}=\boxed{13}\\\\\\(9\sqrt8-3\sqrt{18})\cdot\sqrt2=9\sqrt{8\cdot2}-3\sqrt{18\cdot2}=9\sqrt{16}-3\sqrt{36}=\\\\=9\sqrt{4^2}-3\sqrt{6^2}=9\cdot4-3\cdot6=36-18=\boxed{18}[/tex]
Odpowiedź:
zad 3
√(1 9/16) = √(25/16) = 5/4 = 1 1/4
√(144 + 25) = √169 = 13
(9√8 - 3√18) * √2 = [9√(4 * 2) - 3√(9 * 2)] = (9 * 2√2 - 3 * 3√2) * √2 =
= (18√2 - 9√2) * √2 = 9√2 * √2 = 9 * 2 = 18
