Poziom A, b)
[tex]3(x-2)-(x-3)=-(5x-4)\\\\3x-6-x+3=-5x+4\\\\2x-3=-5x+4\\\\2x+5x=4+3\\\\7x=7 \ \ /:7\\\\\huge\boxed{x=1}[/tex]
Poziom B, b)
[tex]\frac{2(x+1)-3}{4}=\frac{x}{5}\\\\\frac{2x+2-3}{4}=\frac{x}{5}\\\\\frac{2x-1}{4}=\frac{x}{5} \ \ /\cdot20\\\\5(2x-1)=4x\\\\10x-5=4x\\\\10x-4x=5\\\\6x=5 \ \ /:6\\\\\huge\boxed{x=\frac{5}{6}}[/tex]
Poziom C, b)
[tex](x+4)(x-1)=x(x+2)+9x-1\\\\x^2-x+4x-4=x^2+2x+9x-1\\\\x^2+3x-4=x^2+11x-1\\\\x^2+3x-x^2-11x=-1+4\\\\-8x=3 \ \ /:(-8)\\\\\huge\boxed{x=-\frac{3}{8}}[/tex]
