Odpowiedź :
Odpowiedź:
[tex]a)\\\\\frac{5x-3}{4}+3=2x\ \ |\cdot4\\\\5x-3+12=8x\\\\5x+9=8x\\\\5x-8x=-9\\\\-3x=-9\ \ |:(-3)\\\\x=3\\\\\\b)\\\\x-\frac{2x+3}{5}=3\ \ |\cdot5\\\\5x-(2x+3)=15\\\\5x-2x-3=15\\\\3x=15+3\\\\3x=18\ \ |:3\\\\x=6[/tex]
[tex]c)\\\\4-\frac{x}{4}=2x-\frac{1}{2}\ \ |\cdot4\\\\16-x=8x-2\\\\-x-8x=-2-16\\\\-9x=-18\ \ |:(-9)\\\\x=2\\\\\\d)\\\\\frac{2x}{3}+4=\frac{x+2}{3}\ \ |\cdot3\\\\2x+12=x+2\\\\2x-x=2-12\\\\x=-10[/tex]
[tex]e)\\\\\frac{3x-2}{5}-2=\frac{x}{5}\ \ |\cdot5\\\\3x-2-10=x\\\\3x-12=x\\\\3x-x=12\\\\2x=12\ \ |:2\\\\x=6[/tex]
Odpowiedź:
a)
[tex]\frac{5x-3}{4}+3=2x[/tex] |*4
5x-3+12=8x
5x-8x = -9
-3x = -9 |:(-3)
x = 3
b)
[tex]x-\frac{2x+3}{5} =3[/tex] |*5
5x-2x-3 = 15
3x = 15+3
3x = 18 |:3
x = 6
c)
[tex]4-\frac{x}{4} =2x-\frac{1}{2}[/tex] |*4
16-x = 8x - 2
-x -8x = -2-16
-9x = -18 |:(-9)
x = 2
d)
[tex]\frac{2x}{3} +4=\frac{x+2}{3}|*3[/tex] |*3
2x + 12 = x+2
2x-x = 2-12
x = -10
e)
[tex]\frac{3x-2}{5}-2=\frac{x}{5}[/tex] |*5
3x-2-10=5
3x-12=5
3x = 5+12
3x = 17 |:3
[tex]x=5\frac{2}{3}[/tex]
Szczegółowe wyjaśnienie: