Odpowiedź:
[tex]P=\frac{a^2\sqrt{3}}{4}\\\\\\a)\ \ a=0,6\\\\P=\dfrac{0,6^2\sqrt{3}}{4}=\dfrac{\not0,36^{0,09}\sqrt{3}}{\not4_{1}}=0,09\sqrt{3}\\\\\\b)\ \ a=1\frac{3}{5}\\\\P=\dfrac{(1\frac{3}{5})^2\sqrt{3}}{4}=\dfrac{(\frac{8}{5})^2\sqrt{3}}{4}=\dfrac{\frac{64}{25}\sqrt{3}}{4}=\frac{64}{25}\sqrt{3}\cdot\frac{1}{4}=\frac{64}{100}\sqrt{3}=0,64\sqrt{3}\\\\\\c)\ \ a=2\sqrt{2}\\\\P=\dfrac{(2\sqrt{2})^2\sqrt{3}}{4}=\dfrac{4\cdot2\sqrt{3}}{4}=\dfrac{\not8^2\sqrt{3}}{\not4_{1}}=2\sqrt{3}[/tex]
[tex]d)\ \ a=3\sqrt{3}\\\\P=\dfrac{(3\sqrt{3})^2\sqrt{3}}{4}=\dfrac{9\cdot3\sqrt{3}}{4}=\dfrac{27\sqrt{3}}{4}=\frac{27}{4}\sqrt{3}=6\frac{3}{4}\sqrt{3}=6,75\sqrt{3}\\\\\\e)\ \ a=4\sqrt{5}\\\\P=\dfrac{(4\sqrt{5})^2\sqrt{3}}{4}=\dfrac{\not16^4\cdot5\sqrt{3}}{\not4_{1}}=4\cdot5\sqrt{3}=20\sqrt{3}[/tex]
