Obliczenia
[tex]4,8+\frac{1}{3}(1,2-0,6)=4,8+\frac{1}{3}\cdot0,6=\\\\=4,8+\frac{1}{\not3_1}\cdot\frac{\not6^2}{10}=4,8+\frac{2}{10}=4,8+0,2=\boxed5[/tex]
