Odpowiedź:
zad 7
a) (1,4)⁷ : (1,4)⁵ = (1,4)⁷⁻⁵ = (1,4)² = 1,96
b) (2/7)⁵ * 7⁵ = (2/7 * 7)⁵ = 2⁵ = 32
c) (2/7)⁵ * (3 1/2)⁶ = (2/7)⁵ * (7/2)⁶ = (2/7)⁵ *(2/7)⁻⁶ =(2/7)⁵⁻⁶ = (2/7)⁻¹ =(7/2)¹ = 7/2 = 3,5
d) (36² * 6⁴)/6⁴ = [(6²)² * 6⁴]/6⁴ = (6⁴ * 6⁴)/6⁴ = 6⁴⁺⁴/6⁴ = 6⁸/6⁴ =6⁸⁻⁴ = 6⁴ = 1296
zad 8
a) (2⁶ + 2⁷)/12 = 2⁶(1 + 2)/12 = 64 * 3/12 = 192/12 = 16
b) (4² * 3⁴)/6³ = [(2²)² * 3⁴]/6³ = (2⁴ * 3⁴)/6³ = (2 * 3)⁴/6³ = 6⁴/6³ = 6⁴⁻³ = 6¹ = 6
zad 9
a) ( 1 1/7)² = (8/7)² = 64/49 = 1 15/49
b) ( - 1 2/3)³ =- (5/3)³ = - 125/27 = - 4 17/27
c) - 1,1² = - 1,21
d) (- 4/9)⁰ = 1 ponieważ każda liczba podniesiona do potęgi 0 jest równa 1
