Odpowiedź:
[tex]a)\ \ 2x^2-8y\ \ \ \ \ \ dla\ \ x=-3\ \ i\ \ y=-2\\\\2x^2-8y=2\cdot(-3)^2-8\cdot(-2)=2\cdot9+16=18+16=34\\\\\\b)\ \ \frac{m^3+4n}{6}\ \ \ \ dla\ \ m=1\ \ i\ \ n=2\\\\\frac{m^3+4n}{6}=\frac{1^3+4\cdot2}{6}=\frac{1+8}{6}=\frac{9}{6}=1\frac{3}{6}=1\frac{1}{2}\\\\\\c)\ \ 2,5\cdot(z-1)(z+1)\ \ \ \ dla\ \ z=5\\\\2,5\cdot(z-1)(z+1)=2,5\cdot(5-1)(5+1)=2,5\cdot4\cdot6=10\cdot6=60[/tex]
[tex]d)\ \ a(b-7)^2\ \ \ \ dla\ \ a=2\ \ i\ \ b=5\\\\a(b-7)^2=2\cdot(5-7)^2=2\cdot(-2)^2=2\cdot4=8\\\\\\e)\ \ cd^2-c^2d\ \ \ \ dla\ \ c=-1\ \ i\ \ d=-2\\\\cd^2-c^2d=-1\cdot(-2)^2-(-1)^2\cdot(-2)=-1\cdot4-1\cdot(-2)=-4+2=-2\\\\\\f)\ \ p^2(2r-3)\ \ \ \ dla\ \ p=-2\ \ i\ \ r=6\\\\p^2(2r-3)=(-2)^2\cdot(2\cdot6-3)=4\cdot(12-3)=4\cdot9=36[/tex]
