Rozwiązane

potrzebuje na szybko plisss​



Potrzebuje Na Szybko Plisss class=

Odpowiedź :

Basetla

[tex]a)\\(-3)^{2} = (-3)\cdot(-3) = 9\\\\-3^{2} = -3\cdot 3 = -9\\\\(-3)^{2} > -3^{2}[/tex]

[tex]b)\\(-4)^{3} =(-4)\cdot(-4)\cdot(-4) = -64\\\\-4^{3} = -4\cdot4\cdot4 = -64\\\\*(-4)^{3} = -4^{3}[/tex]

[tex]c)\\(\frac{1}{2})^{3} = \frac{1}{2}\cdot\frac{1}{2}\cdot\frac{1}{2} = \frac{1}{8}\\\\\frac{1^{3}}{2} =\frac{1\cdot1\cdot1}{2} = \frac{1}{2}\\\\(\frac{1}{2})^{3} < \frac{1^{3}}{2}[/tex]

АDAMiAK

Ćw.1

[tex]a)(-3)^{2}=9\\-3^{2}=-9[/tex]

9>-9

[tex]b)(-4)^{3}=-64\\-4^{3}=-64[/tex]

-64=-64

[tex]c)(\frac{1}{2}) ^{3}=\frac{1}{8}\\\frac{1^{3}}{2}=\frac{1}{2}[/tex]

1/2>1/8