Obliczenia
[tex](1,6)^2-(0,6)^2=(1\frac{6}{10})^2-(\frac{6}{10})^2=\\\\=(1\frac{3}{5})^2-(\frac{3}{5})^2=(\frac{8}{5})^2-\frac{3^2}{5^2}=\frac{8^2}{5^2}-\frac{9}{25}=\\\\=\frac{64}{25}-\frac{9}{25}=\frac{55}{25}=2\frac{5}{25}=2\frac{1}{5}=2\frac{2}{10}=\boxed{2,2}[/tex]