Rozwiąż równania elementarne (załącznik)

a) 5x + 9 = 17
5x = 8 | :5
[tex]x = \frac{8}{5} = 1\frac{3}{5}[/tex]
b) 11 - 2x = -4
-2x = -15 |*(-1)
2x = 15 |:2
[tex]x = \frac{15}{2} = 7\frac{1}{2}[/tex]
c) -x +7 = 13
-x = 6 |*(-1)
x = -6
d) 11 - a = -3
-a = -14 |*(-1)
a = 14
e) 6x + 13 = -7
6x = -20 |:6
[tex]x = -\frac{20}{6} = 3\frac{2}{6} = 3\frac{1}{3}[/tex]
f) 5x + 8 = 4x - 2
x = -10
g) 9x - 16 = 2 + 7x
2x = 18 |:2
x = 9
h) 15 - 5x = 7x + 1
-12x = -14 |: (-1)
12x = 14 |:12
x = [tex]\frac{14}{12} = 1\frac{2}{12} = 1\frac{1}{6}[/tex]
i) 9x + 8 = 8 - 4x
5x = 0 |:5
x = 0
Zad 2
a)
[tex]\frac{x}{8} = \frac{(x+8)}{4} = x*4 = 8*(x+8)\\ 4x = 8x+64 \\-4x = 64 |*(-1)\\4x = -64 |:4\\x = -16[/tex]
b)
[tex]\frac{(2x-6)}{5} = \frac{(x+8)}{4} \\4(2x-6) = 5(x+8) \\8x - 24 = 5x +40\\3x = 64 |:3\\x = \frac{64}{3} = 21\frac{1}{3}[/tex]
c)
[tex]\frac{(3x-5)}{3} = \frac{(2x + 8)}{5}\\3(2x+8) = 5(3x-5) \\6x+24 = 15x - 25\\49 = 9x\\x = \frac{49}{9} = 5\frac{4}{9}[/tex]
Powodzenia ;)