Obliczenia
[tex]\frac{1}{3}+\frac{3}{4}=\frac{4}{12}+\frac{3}{12}=\frac{7}{12}\\\\\frac{2}{5}+\frac{3}{4}=\frac{8}{20}+\frac{15}{20}=\frac{23}{20}=1\frac{3}{20}\\\\\frac{\not2^1}{3}\cdot\frac{1}{\not6_3}=\frac{1}{9}\\\\\frac{4}{7}:\frac{2}{5}=\frac{\not4^2}{7}\cdot\frac{5}{\not2_1}=\frac{10}{7}=1\frac{3}{7}\\\\\frac{3}{5}\cdot\frac{2}{5}=\frac{6}{25}[/tex]
