Odpowiedź:
[tex]a)\ \ (a^2b^3c)^6\cdot(ab^2c^2d)^4=(a^2)^6\cdot(b^3)^6\cdot c^6\cdot a^4\cdot(b^2)^4\cdot(c^2)^4\cdot d^4=\\\\=a^{12}\cdot b^{18}\cdot c^6\cdot a^4\cdot b^8\cdot c^8\cdot d^4=a^{12+8}\cdot b^{18+8}\cdot c^{6+8}\cdot d^4=a^{16}b^{26}c^{14}d^4[/tex]
[tex]b)\ \ 418\frac{1}{5}-526\frac{1}{6}=\frac{2091}{5}-\frac{3157}{6}=\frac{12546}{30}-\frac{15785}{30}=-\frac{3239}{30}=-107\frac{29}{30}\\\\\\3)\ \ 2(x-3)^2+5(x-4)(x+4)+3(x+4)^2=\\\\=2(x^2-6x+9)+5(x^2-16)+3(x^2+8x+16)=\\\\=2x^2-12x+18+5x^2-80+3x^2+24x+48=10x^2+12x-14[/tex]
