Odpowiedź:
Szczegółowe wyjaśnienie:
[tex]a = 12 \ cm\\H = 8 \ cm\\P_{c} = ?\\V = ?\\\\P_{c} = 2P_{p}+P_{b}\\\\P_{p} = 6\cdot\frac{a^{2}\sqrt{3}}{4} = \frac{3a^{2}\sqrt{3}}{2}\\\\P_{p} = \frac{3\cdot12^{2}\sqrt{3}}{2} = \frac{3\cdot144\sqrt{3}}{2} =3\cdot72\sqrt{3}=216\sqrt{3} \ cm^{2}\\\\P_{b} = 6\cdot a\cdot H = 6\cdot12\cdot8 = 576 \ cm^{2}\\\\{P_{c} = 2\cdot216\sqrt{3} \ cm^{2}+576 \ cm^{2}[/tex]
[tex]\boxed{P_{c} = (432\sqrt{3}+576) \ cm^{2}}[/tex]
[tex]V = P_{p}\cdot H\\\\V = 216\sqrt{3} \ cm^{2}\cdot 8 \ cm[/tex]
[tex]\boxed{V = 1728\sqrt{3} \ cm^{3}}[/tex]
