1.
[tex]dane:\\m =125 \ g\\V = 50 \ cm^{3}}\\szukane:\\d = ?\\\\d = \frac{m}{V}\\\\d = \frac{125 \ g}{50 \ cm^{3}}\\\\\boxed{d = 2,5\frac{g}{cm^{3}} \ - porcelana}[/tex]
3.
[tex]dane:\\m = 50 \ g\\d = 8800\frac{kg}{m^{3}} = 8,8\frac{g}{cm^{3}}\\szukane:\\V = ?\\\\d = \frac{m}{V} \ \ \rightarrow \ \ V = \frac{m}{d}\\\\V = \frac{50 \ g}{8,8\frac{g}{cm^{3}}}\\\\\boxed{V = 5,68(18) cm^{3}\approx5,7 \ cm^{3}}[/tex]
5.
[tex]dane:\\V = 0,6 \ m^{3}\\d = 2,7\frac{g}{cm^{3}} = 2700\frac{kg}{m^{3}}\\szukane:\\m = ?\\\\d = \frac{d}{V} \ \ \rightarrow \ \ m = d\cdot V\\\\m = 2700\frac{kg}{m^{3}}\cdot0,6 \ m^{3}\\\\\boxed{m = 1 \ 620 \ kg}[/tex]
