Odpowiedź i szczegółowe wyjaśnienie:
[tex]\dfrac{30t-10}{5}=\dfrac{30}{5}t-\dfrac{10}{5}=6t-2\\\\\\-\dfrac{7,5a-9}{3}=-\dfrac{7,5a}{3}+\dfrac93=-2,5a+3\\\\\\-10\cdot\dfrac{y+11}{-2}=\dfrac{-10}{-2}\cdot(y+11)=5(y+11)=5y+55\\\\\\\dfrac{x+10}{-16}\cdot8=\dfrac{x+10}{-2\cdot8}\cdot8=\dfrac{x+10}{-2}=-0,5x-5[/tex]
