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[tex](5\frac{1}{8}-2\frac{5}{6})\cdot(\frac{2}{5}+\frac{2}{7})=(5\frac{3}{24}-2\frac{20}{24})\cdot(\frac{14}{35}+\frac{10}{35})=\\\\=(4\frac{27}{24}-2\frac{20}{24})\cdot\frac{24}{35}=2\frac{7}{24}\cdot\frac{24}{35}=\frac{55}{24}\cdot\frac{24}{35}=\frac{55}{35}=\frac{11}{7}=1\frac{4}{7}[/tex]
