Odpowiedź:
Szczegółowe wyjaśnienie:
25.
a)
[tex]\frac{2}{5}*1,5-\frac{3}{10}+0,7=\frac{4}{10}*1,5-0,3+0,7=0,4*1,5-0,3+0,7=0,6-0,3+0,7=0,3+0,7=1[/tex]
b)
[tex]7\frac{1}{7}*0,07-5\frac{5}{8}*1,6=\frac{50}{7}*\frac{7}{100}-\frac{45}{8}*\frac{16}{10}=\frac{1}{2}-\frac{45}{8}*\frac{8}{5}=\frac{1}{2}-9=-8\frac{1}{2}[/tex]
c)
[tex]-2,34*3\frac{11}{13}+1,26*5\frac{5}{9}=-\frac{117}{50}*\frac{50}{13}+\frac{63}{50}*\frac{50}{9}=-9+7=-2[/tex]
d)
[tex]\frac{3,07-\frac{3}{5}}{2\frac{3}{5}+2,34}=\frac{3,07-\frac{6}{10}}{2\frac{6}{10}+2,34}=\frac{3,07-0,6}{2,6+2,34}=\frac{2,47}{4,94}=\frac{247}{494}=\frac{1}{2}[/tex]
e)
[tex]\frac{-2,7-1\frac{2}{3}}{-18\frac{1}{2}+5,4}=(-2\frac{7}{10}-1\frac{2}{3}):(-18,5+5,4)=(-2\frac{21}{30}-1\frac{20}{30}):(-13,1)=-3\frac{41}{30}:(-13\frac{1}{3})=\frac{131}{30}:\frac{40}{3}=\frac{131}{30}*\frac{3}{40}=\frac{131}{40}=3\frac{11}{40}[/tex]
f)
[tex]\frac{11,2-3\frac{3}{5}}{11\frac{2}{5}+19}=\frac{11,2-3,6}{11,4+19}=\frac{7,6}{30,4}=\frac{76}{304}=\frac{1}{4}[/tex]
