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[tex]\sqrt{121}+\sqrt{144}+\sqrt{64}=\sqrt{11^2}+\sqrt{12^2}+\sqrt{8^2}=11+12+8=31\\\\\sqrt{0,04}+\sqrt{0,09}+\sqrt{0,49}=\sqrt{0,2^2}+\sqrt{0,3^2}+\sqrt{0,7^2}=0,2+0,3+0,7=1,2\\\\\sqrt{7\frac{1}{9}}-\sqrt{1\frac{28}{36}}=\sqrt{\frac{64}{9}}-\sqrt{\frac{64}{36}}=\frac{\sqrt{64}}{\sqrt9}-\frac{\sqrt{64}}{\sqrt{36}}=\frac{\sqrt{8^2}}{\sqrt{3^2}}-\frac{\sqrt{8^2}}{\sqrt{6^2}}=\frac{8}{3}-\frac{8}{6}=\frac{16}{6}-\frac{8}{6}=\frac{8}{6}=\\\\=\frac{4}{3}=1\frac{1}{3}[/tex]
