Odpowiedź:
Szczegółowe wyjaśnienie:
[tex]1. \left \{ {{-x+y=2} \atop {3x-6y=0}} \right. \\\left \{ {{x=-2+y} \atop {3x-6y=0}} \right. \\3(-2+y)-6y=0\\y=-2\\x=-2+(-2)\\x=-4\\\left \{ {{-(-4)+(-2)=2} \atop {3*(-4)-6*(-2)=0}} \right. \\\\\left \{ {{2=2} \atop {0=0}} \right. \\\\(x,y)=(-4,-2)[/tex]
[tex]2.\\ f(-3)=2 f(3)=6\\\left \{ {{-3a+b=2} \atop {3a+b=6}} \right. \\\\\left \{ {{2b=8} \atop {3a+b=6}} \right. \\\\\left \{ {{b=4} \atop {3a+4=6}} \right. \\\\\left \{ {{b=4} \atop {3a=2}} \right. \\\\\left \{ {{b=4} \atop {a=\frac{2}{3} }} \right. \\\\y=\frac{2}{3}x+4[/tex]