[tex]dane:\\V = 6 \ cm\times11 \ cm \times 13 \ cm = 858 \ cm^{3}\\d_1 = 7900\frac{kg}{m^{3}} = 7,9\frac{g}{cm^{3}}\\d_2 = 8960\frac{kg}{m^{3}} = 8,96\frac{g}{cm^{3}}\\d_3 = 600\frac{kg}{m^{3}} = 0,6\frac{g}{cm^{3}}\\szukane:\\m_1, m_2, m_3 = ?[/tex]
Korzystamy ze wzoru na gęstość substancji:
[tex]d = \frac{m}{V} \ \ /\cdot V\\\\\underline{m = d\cdot V}[/tex]
[tex]m_1 = d_1\cdot V = 7,9\frac{g}{cm^{3}}\cdot858 \ cm^{3} = 6 \ 778,2 \ g \approx6,78 \ kg\\\\m_2 = d_2\cdot V = 8,96\frac{g}{cm^{3}}\cdot858 \ cm^{3} = 7 \ 687,68 \ g \approx 7,69 \ kg\\\\m_3 = d_3\cdot V = 0,6\frac{g}{cm^{3}}\cdot858 \ cm^{3} =514,8 \ g \approx 0,51 \ kg[/tex]
