Odpowiedź :
Odpowiedź:
Wyjaśnienie:
a) propan — 2-bromopropan — propan-2-ol
H H H H H H H H H
I I I I I I I I I
H - C - C- C-H +Br2------>H-C-C- C-H +NaOH-->H-C- C- C -H + NaBr
I I I -HCl I I I I I I
H H H H Br H H OH H
b) but-1-en — 2-bromobutan — butan-2-ol —
H H H H H H H H H H H H
I I I I I I I I I I I I
H - C - C- C=C-H +HBr-->H-C-C- C- C-H +NaOH-->H-C- C- C -C-H + NaBr
I I I I I I I I I I
H H H H Br H H H OH H
I
↓ -H2O
H H H
I I I
H- C - C= C -C-H --> but-2-en
I I I
H H H
c) propan — 1-chloropropan — propan-1-ol
H H H H H H H H H
I I I I I I I I I
H - C - C- C -H +Cl2------>H-C-C- C-Cl +NaOH - --> 2H-C- C- C -OH +2K -->
I I I -HCl I I I -NaCl I I I
H H H H H H H H H
propan-1-olan potasu
H H H
I I I
--------> H-C- C - C - OK +H2
I I I
H H H
d) but-2-yn but-2-en butan-2-ol
H H H H H H H H
I I I I I I I I
H - C - C≡ C -C -H +H2----->H-C-C= C- C-H +H2O---+H-->H- C- C- C - C -H I I l I I I I I I I
H H H H H H H H OH H