[tex]\frac{4x^{2} + 18x + 18}{x + 1} = 2 , x\neq 1\\4x^{2} + 18x + 18 = 2(x + 1)\\4x^{2} + 18x + 18 - 2(x + 1) = 0\\4x^{2} + 18x + 18 - 2x -2 = 04x^{2} + 16x + 16 = 0\\4(x^{2} + 4x + 4) = 0\\4(x + 2)^{2} = 0\\(x + 2)^{2} = 0\\x + 2 = 0\\x = -2[/tex]
Odpowiedź:
x = -2