[tex]a)\\\\\frac{x}{4} = \frac{5}{9} \ \ |\cdot36\\\\9x = 20 \ \ /:9\\\\x = \frac{20}{9}\\\\\boxed{x = 2\frac{2}{9}}[/tex]
[tex]b)\\\\\frac{x-2}{3} = \frac{x}{4} \ \ |\cdot 12\\\\4(x-2) = 3x\\\\4x - 8 = 3x\\\\4x-3x = 8\\\\\boxed{x = 8}[/tex]
Odpowiedź:
Szczegółowe wyjaśnienie:
