Cześć!
a)
[tex]1\dfrac{3}{5}-\dfrac{1}{2}=1\dfrac{3\cdot2}{5\cdot2}-\dfrac{1\cdot5}{2\cdot5}=1\dfrac{6}{10}-\dfrac{5}{10}=\boxed{1\frac{1}{10}}\\[/tex]
b)
[tex]3\dfrac{5}{6}-1\dfrac{1}{4}=3\dfrac{5\cdot2}{6\cdot2}-1\dfrac{1\cdot3}{4\cdot3}=3\dfrac{10}{12}-1\dfrac{3}{12}=\boxed{2\frac{7}{12}}\\[/tex]
c)
[tex]4\dfrac{1}{2}-1\dfrac{1}{4}=4\dfrac{1\cdot2}{2\cdot2}-1\dfrac{1}{4}=4\dfrac{2}{4}-1\dfrac{1}{4}=\boxed{3\frac{1}{4}}\\[/tex]
