Odpowiedź :
Cześć!
a)
[tex]2\dfrac{5}{7}=\dfrac{2\cdot7+5}{7}=\dfrac{14+5}{7}=\dfrac{19}{7}\\\\\\2\dfrac{7}{8}=\dfrac{2\cdot8+7}{8}=\dfrac{16+7}{8}=\dfrac{23}{8}\\\\\\2\dfrac{3}{10}=\dfrac{2\cdot10+3}{10}=\dfrac{20+3}{10}=\dfrac{23}{10}[/tex]
b)
[tex]5\dfrac{1}{3}=\dfrac{5\cdot3+1}{3}=\dfrac{15+1}{3}=\dfrac{16}{3}\\\\\\5\dfrac{8}{11}=\dfrac{5\cdot11+8}{11}=\dfrac{55+8}{11}=\dfrac{63}{11}\\\\\\5\dfrac{4}{15}=\dfrac{5\cdot15+4}{15}=\dfrac{75+4}{15}=\dfrac{79}{15}[/tex]
c)
[tex]6\dfrac{4}{7}=\dfrac{6\cdot7+4}{7}=\dfrac{42+4}{7}=\dfrac{46}{7}\\\\\\6\dfrac{5}{9}=\dfrac{6\cdot9+5}{9}=\dfrac{54+5}{9}=\dfrac{59}{9}\\\\\\6\dfrac{13}{15}=\dfrac{6\cdot15+13}{15}=\dfrac{90+13}{15}=\dfrac{103}{15}[/tex]
Odpowiedź:
a)[tex]2\frac{5}{7}=\frac{19}{7}[/tex]
[tex]2\frac{7}{8} =\frac{23}{8}[/tex]
[tex]2\frac{3}{10} =\frac{23}{10}[/tex]
b)[tex]5\frac{1}{3} =\frac{16}{3}[/tex]
[tex]5\frac{8}{11} =\frac{63}{11}[/tex]
[tex]5\frac{4}{15} =\frac{79}{15}[/tex]
c)[tex]6\frac{4}{7} =\frac{46}{7}[/tex]
[tex]6\frac{5}{9} =\frac{59}{9}[/tex]
[tex]6\frac{13}{15} =\frac{103}{15}[/tex]
Szczegółowe wyjaśnienie: