zad. 1
1) pierwiastek z 32/81=
2) pierwiastek z 0,04=
3) pierwiastek z 2,25=
4) pierwiastek z 23,04=
5) pierwiastek z 12,10=



Odpowiedź :

Krysia

[tex]1)\\\\\sqrt{\frac{32}{81}}=\sqrt{\frac{16*2}{81}}=\sqrt{\frac{16}{81}*2}=\sqrt{\frac{16}{81} }*\sqrt{2}=\sqrt{(\frac{4}{9})^2 }*\sqrt{2}=\frac{4}{9}\sqrt{2}\\\\2)\\\\\sqrt{0,04}=\sqrt{(0,02)^2}=0,2\\\\3)\\\\\sqrt{2,25}=\sqrt{(1,5)^2}[/tex]

[tex]4)\\\\\sqrt{23,04}=\sqrt{ \frac{2304}{100}} =\sqrt{\frac{576}{25}} =\sqrt{(\frac{ 24}{ 5})^2}=\frac{24}{5}=4\frac{4}{5}\\\\5)\\\\\sqrt{12,10}=\sqrt{\frac{1210}{100}}==\sqrt{\frac{121 *10}{100}}=\sqrt{\frac{121}{100}*10}=\sqrt{\frac{121}{100} } *\sqrt{10}=\\\\\\=\sqrt{(\frac{11}{10 } )^2} *\sqrt{10} =\frac{11}{10}*\sqrt{10}=1,1 \sqrt{10}[/tex]